X^2-3x+4+4x^2+5x-3=x

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Solution for X^2-3x+4+4x^2+5x-3=x equation: 



X^2-3X+4+4X^2+5X-3=X

We move all terms to the left:

X^2-3X+4+4X^2+5X-3-(X)=0

We add all the numbers together, and all the variables

5X^2+X+1=0

a = 5; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·5·1
Δ = -19
Delta is less than zero, so there is no solution for the equation

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